Ответ:
\(\cos(3\pi-\beta)=-\cos\beta\), \(\sin(\beta-\frac{3\pi}{2})=\cos\beta\), \(\cos(\beta-\pi)=-\cos\beta\).
\[\frac{-\cos\beta-\cos\beta}{5(-\cos\beta)}=\frac{-2\cos\beta}{-5\cos\beta}=\frac25.\]
Ответ: \(\frac25\).
\(\cos(3\pi-\beta)=-\cos\beta\), \(\sin(\beta-\frac{3\pi}{2})=\cos\beta\), \(\cos(\beta-\pi)=-\cos\beta\).
\[\frac{-\cos\beta-\cos\beta}{5(-\cos\beta)}=\frac{-2\cos\beta}{-5\cos\beta}=\frac25.\]
Ответ: \(\frac25\).