19) g(2-x) / g(2+x), если g(x) = ∛x(4-x) при |x|≠2

19)

$$g(2 - x) = \sqrt[3]{(2 - x)(4 - (2 - x))} = \sqrt[3]{(2 - x)(4 - 2 + x)} = \sqrt[3]{(2 - x)(2 + x)} = \sqrt[3]{4 - x^2}$$

$$g(2 + x) = \sqrt[3]{(2 + x)(4 - (2 + x))} = \sqrt[3]{(2 + x)(4 - 2 - x)} = \sqrt[3]{(2 + x)(2 - x)} = \sqrt[3]{4 - x^2}$$

$$\frac{g(2 - x)}{g(2 + x)} = \frac{\sqrt[3]{4 - x^2}}{\sqrt[3]{4 - x^2}} = 1$$

Ответ: 1