4) $$ \left( \frac{1}{7} \right)^{x^2-2x-2} = \frac{1}{7} $$
$$ x^2 - 2x - 2 = 1 $$
$$ x^2 - 2x - 3 = 0 $$
$$ (x-3)(x+1) = 0 $$
$$ x_1 = 3, x_2 = -1 $$
Ответ: 3, -1