4) $$\frac{\sin x - \cos x}{1 - tgx} = \frac{\sin x - \cos x}{1 - \frac{\sin x}{\cos x}} = \frac{\sin x - \cos x}{\frac{\cos x - \sin x}{\cos x}} = \frac{(\sin x - \cos x)\cos x}{\cos x - \sin x} = \frac{-(\cos x - \sin x)\cos x}{\cos x - \sin x} = -\cos x$$. Тождество доказано.