296 1) \(\frac{\log_2 24 - \frac{1}{2} \log_2 72}{\log_3 18 - \frac{1}{3} \log_3 72}\)

Используем свойства логарифмов: \(c \log_a b = \log_a b^c\), \(\log_a b - \log_a c = \log_a \frac{b}{c}\) и \(\frac{\log_a b}{\log_a c} = \log_c b\). \(\frac{\log_2 24 - \frac{1}{2} \log_2 72}{\log_3 18 - \frac{1}{3} \log_3 72} = \frac{\log_2 24 - \log_2 \sqrt{72}}{\log_3 18 - \log_3 \sqrt[3]{72}} = \frac{\log_2 \frac{24}{\sqrt{72}}}{\log_3 \frac{18}{\sqrt[3]{72}}} = \frac{\log_2 \frac{24}{6\sqrt{2}}}{\log_3 \frac{18}{2\sqrt[3]{9}}} = \frac{\log_2 \frac{4}{\sqrt{2}}}{\log_3 \frac{9}{\sqrt[3]{9}}} = \frac{\log_2 2^{\frac{3}{2}}}{\log_3 9^{\frac{2}{3}}} = \frac{\frac{3}{2}}{\frac{2}{3} \cdot 2} = \frac{\frac{3}{2}}{\frac{4}{3}} = \frac{9}{8}\).
Ответ: 9/8