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МатематикаВопрос:
15) p⁴⁰ ⋅ p³⁰ ⋅ p²⁰ =
Ответ:
Для решения данного примера необходимо воспользоваться свойством степеней с одинаковым основанием: $$a^m \cdot a^n = a^{m+n}$$.
В нашем случае: $$p^{40} \cdot p^{30} \cdot p^{20} = p^{40+30+20} = p^{90}$$
Ответ: p⁹⁰
Похожие
- 2) x⁷ ⋅ x⁹ =
- 3) c³ ⋅ c⁴ =
- 4) b⁵ ⋅ b¹¹ =
- 5) k⁵ ⋅ k⁷ =
- 6) m¹⁰ ⋅ m²⁰ =
- 7) t⁸ ⋅ t⁵ =
- 8) a¹³ ⋅ a³ =
- 9) n⁹ ⋅ n⁸ =
- 10) p² ⋅ p³ ⋅ p⁴ =
- 11) y⁵ ⋅ y² ⋅ y⁶ =
- 12) c⁵ ⋅ c⁵ ⋅ c⁵ =
- 13) x⁴ ⋅ x⁹ ⋅ x² =
- 14) b¹⁰ ⋅ b²⁰ ⋅ b¹⁵ =
- 17) k¹² : k³ =
- 18) p²⁰ : p¹⁰ =
- 19) y¹⁶ : y⁴ =
- 20) n⁶ : n² =
- 21) a¹⁸ : a⁶ =
- 22) x⁹ / x³ =
- 23) b²⁴ / b⁸ =
- 24) m³⁰ / m¹⁰ =
- 25) c²⁷ / c⁹ =
- 26) t¹⁵ / t⁵ =
- 27) k³⁶ / k⁶ =
- 28) q¹⁰ / q² =
- 29) n²¹ / n⁷ =
- 30) x²⁵ / x⁶ =
- 32) (a⁵ ⋅ a¹⁰) / a¹³ =
- 33) (n¹⁶ ⋅ n) / n⁸ =
- 34) (c⁴ ⋅ c¹⁴) / c¹⁰ =
- 35) (b¹² : b³) / b² =
- 36) (k¹⁵ : k³) / k¹¹ =
- 37) (x⁶ ⋅ x⁴ ⋅ x⁹) / (x⁶ ⋅ x⁴) =
- 38) (q² ⋅ q⁷ ⋅ q⁶) / (q⁹ ⋅ q⁰) =
- 39) (y²⁰ ⋅ y³⁰) / (y¹⁰ ⋅ y⁰ ⋅ y¹⁰) =
- 40) (m³² : m⁴) / (m¹² ⋅ m⁰ ⋅ m³) =
- 41) (x⁸ ⋅ x¹²) / (y⁴⁰ : y²⁵ : y) =
- 42) c¹⁹ : c¹¹ / (c²⁰ ⋅ c⁵ : c¹⁸) =
- 43) t⁴⁰ ⋅ (t⁶⁰ : t²⁰) : (t¹⁰⁰ : t⁵⁰) =
- 44) (b³ⁿ ⋅ b⁷ⁿ) / (b²ⁿ ⋅ b⁰ ⋅ b¹ⁿ) =
- 45) (q²⁰ⁿ : q⁰) / (q¹³ⁿ : q⁸ⁿ ⋅ q¹¹ⁿ) =
