По теореме синусов: sin(A)/a = sin(B)/b; sin(A)/9 = sin(56)/8; sin(A) = 9 * sin(56) / 8; sin(A) ≈ 0.935; A ≈ arcsin(0.935) ≈ 69.3°
Найдем угол C: C = 180 - A - B; C = 180 - 69.3 - 56 = 54.7°
Найдем сторону c по теореме синусов: c/sin(C) = b/sin(B); c = b * sin(C) / sin(B); c = 8 * sin(54.7) / sin(56); c ≈ 7.88
Ответ: ∠A ≈ 69.3°, ∠C ≈ 54.7°, c ≈ 7.88