Ответ:
\(f'(x)=\frac{2}{\sqrt{x}}-\frac{1}{10x^2}\).
При \(x=\frac19\): \(f'(\frac19)=\frac{2}{1/3}-\frac{1}{10/81}=6-\frac{81}{10}=-\frac{21}{10}\).
Ответ: \(f'(1/9)=-\frac{21}{10}\).
\(f'(x)=\frac{2}{\sqrt{x}}-\frac{1}{10x^2}\).
При \(x=\frac19\): \(f'(\frac19)=\frac{2}{1/3}-\frac{1}{10/81}=6-\frac{81}{10}=-\frac{21}{10}\).
Ответ: \(f'(1/9)=-\frac{21}{10}\).